Home›Specific-heat-capacity Conversion›Convert joule-per-kilogram-per-kelvin to btu-it-per-pound-per-°f
J/(kg*K) to BTU(IT)/lb/°F Converter
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J/(kg*K)
0.000239
1J/(kg*K) × (1 / 4186.800000009) = 0.000238846
→ Rounded to display: 0.000239
How to Convert J/(kg*K) to BTU(IT)/lb/°F
Example:
15 J/(kg*K) = 0.003583 BTU (IT) per pound per °F
1 J/(kg*K) = 0.000239 BTU (IT) per pound per °F | 1 BTU (IT) per pound per °F = 4186.8 J/(kg*K)
Conversion Steps:
15 × (1 / 4186.800000009) = 0.003582688
Conversion table from J/(kg*K) to BTU(IT)/lb/°F
| J/(kg*K) [J/(kg*K)] | BTU(IT)/lb/°F [] |
|---|---|
| 0.01 J/(kg*K) | 0.000002 |
| 0.1 J/(kg*K) | 0.000024 |
| 1 J/(kg*K) | 0.000239 |
| 2 J/(kg*K) | 0.000478 |
| 3 J/(kg*K) | 0.000717 |
| 5 J/(kg*K) | 0.001194 |
| 10 J/(kg*K) | 0.002388 |
| 20 J/(kg*K) | 0.004777 |
| 50 J/(kg*K) | 0.011942 |
| 100 J/(kg*K) | 0.023885 |
| 1000 J/(kg*K) | 0.238846 |